Balance the following equation with steps and explaination: 1. KClO3+ C12H22O11KCl+ CO2+ H2O
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Answer:
we will solve it by variable method
Let
A(KClO3) + B(C12H22O11KCl) + C(CO2) + D( H2O)
Here,
A = B
11B = C2
22B = D
putting the value of B = 1 because it the the biggest compound in this equation.
A = 1
11 × 1 = 2C
11/2 = C
C = 11/2
22×1 = D
D = 22
As we know the value of C is in fraction so we will multiply all variables by 2
A = 1×2 = 2
C = 11/2 × 2 = 11
D = 22 × 2 = 44
put the values of A,B,C and D
2(KClO3) + (C12H22O11KCl) + 11(CO2) + 44( H2O)
Hence, the equation is balanced.
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Balanced Chemical Equation
8KClO3 + C12H22O11 → 8KCl + 12CO2 + 11H2O
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