Chemistry, asked by Rishita2003, 6 months ago

Balance the following equation with steps and explaination: 1. KClO3+ C12H22O11KCl+ CO2+ H2O

Answers

Answered by Anonymous
0

Answer:

we will solve it by variable method

Let

A(KClO3) + B(C12H22O11KCl) + C(CO2) + D( H2O)

Here,

A = B

11B = C2

22B = D

putting the value of B = 1 because it the the biggest compound in this equation.

A = 1

11 × 1 = 2C

11/2 = C

C = 11/2

22×1 = D

D = 22

As we know the value of C is in fraction so we will multiply all variables by 2

A = 1×2 = 2

C = 11/2 × 2 = 11

D = 22 × 2 = 44

put the values of A,B,C and D

2(KClO3) + (C12H22O11KCl) + 11(CO2) + 44( H2O)

Hence, the equation is balanced.

Answered by raghvendrark500
0

Balanced Chemical Equation

8KClO3 + C12H22O11 → 8KCl + 12CO2 + 11H2O

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