Chemistry, asked by asonika833, 1 month ago

Balance the following equations :
1) AL2O3 + HCI = ALCI3 + H2O
2) Na2SO3 + HCl = NaCl + H2O + SO2
3) MgCl2 + NaOH = Mg(OH)2 + NaCl
4) KOH + CO2 = K2CO3 + H2O
5) K + H2O = KOH + H2
6) P + O2 = P2O5
7) Fe + H2O = Fe3O4 + H2
8) KClO3 = KCl + O2
9) H2S + Cl2 = HCl + S
10) Zn + HCl = ZnCl2 + H2
11) Pb3O4 = PbO + O2 ​

Answers

Answered by haripriyayarlagadda4
0

Answer:

1)This is an acid-base reaction (neutralization): Al 2O 3 is a base, HCl is an acid. , [Note: α-Alumina is the main component of technical grade alumina. Corundum is natural Al2O3.

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Search by reactants (Al 2O 3, HCl)

1 HCl + Al2O3 → H2O + AlCl3

2 HCl + Al2O3 → HO3 + Al2Cl

3 HCl + Al2O3 → AlCl3 + HOH

2) This is an acid-base reaction (neutralization): HCl is an acid, Na 2SO 3 is a base.

3)This is a precipitation reaction: Mg(OH) 2 is the formed precipitate.

4)CO2 + H2O → H2CO3 - Balanced equation | Chemical Equations online!

5)Balancing Strategies: This is a single replacement reaction where the potassium atom replaces the hydrogen in H20. When you balance this equation be sure to count all of the hydrogen atoms on the product side of the equation. You should have four hydrogen atoms on the product side of the equation.

6)The balanced equation is "2SO"_2 + "O"_2 → "2SO"_3. Type of Chemical Reaction: For this reaction we have a combination reaction

7)The chemical reaction is given as

Fe + H2O → Fe3O4+ H2

The balanced chemical equation can be written as

3Fe + 4H2O → Fe3O4 + 4H2

8)KClO3 → KCl + O2. 2KClO3 → 2KCl + 3O2.

What A Gold Leaf Electroscope Can: Water Is Cooled From 4oc To 0oc It Will

The Maximum Covalency Of Sulphur Is: Water In Oil Emulsions Is Also Called As

9) H 2S is a reducing agent, Cl 2 is an oxidizing agent. ; Greenish-yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.]

Search by reactants (Cl 2, H 2S) and by products (HCl, S)

1 Cl2 + H2S → HCl + S

2 H2O + Cl2 + H2S → H2SO4 + HCI+S

10)Zn + HCl → ZnCl2 + H.

11)2Pb3O4. 6PbO + O. 2

The thermal decomposition of lead(II,IV) oxide to produce oxide lead(II) and oxygen. This reaction takes place at a temperature of over 550°

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