Math, asked by tek675, 4 months ago

balance the following equations ​

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Answers

Answered by Ladylaurel
8

Answer:-

 \sf{Question:-}

 \sf{{KClO}_{3} \:  \longrightarrow \: KCl + {O}_{2}}

 \bf{Answer:-}

 \sf{{2KClO}_{3} \:  \longrightarrow \: KCl + {3O}_{2}}

Hence, Balanced !

 \sf{Question:-}

 \sf{{H}_{2} \: {O}_{2} \longrightarrow \: {H}_{2} \: O + {O}_{2}}

 \bf{Answer:-}

 \sf{{2H}_{2} \: {O}_{2} \longrightarrow \: {2H}_{2} \: O + {O}_{2}}

Hence, Balanced !

 \sf{Question:-}

 \sf{{CaCO}_{3} + HCl \longrightarrow \: {CaCl}_{2} + {H}_{2} \: O + {CO}_{2}}

 \bf{Answer:-}

 \sf{{CaCO}_{3} + 2HCl \longrightarrow \: {CaCl}_{2} + {H}_{2} \: O + {CO}_{2}}

Hence, Balanced !

 \sf{Question:-}

 \sf{{NaHCO}_{3} \longrightarrow \: {Na}_{2} \: {CO}_{3} + {H}_{2} \: O + {CO}_{2}}

 \bf{Answer:-}

 \sf{{2NaHCO}_{3} \longrightarrow \: {Na}_{2} \: {CO}_{3} + {H}_{2} \: O + {CO}_{2}}

Hence, Balanced !

 \sf{Question:-}

 \sf{{N}_{2} + {H}_{2} \longrightarrow \: {NH}_{3}}

 \bf{Answer:-}

 \sf{{N}_{2} + {3H}_{2} \longrightarrow \: {2NH}_{3}}

Hence, Balanced !

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