Question

Balance the following equations. (answer this to get 10b)
(a) Mg + H2SO4 → MgSO4 + H2
(b) CaCO3 + HCl → CaCl2 + H2O + CO2

Answer 1

Answer:

As we know that,

No. of moles=

mol. wt.

wt.

Now,

Wt. of Mg=6g

Mol. wt. of Mg=24g

No. of moles of Mg in 6g=

24

6

=0.25 moles

Mg+H

2

SO

4

⟶MgSO

4

+H

2

from the above reaction,

1 mole of magnesium sulphate is formed when 1 mole of magnesium reacts.

Therefore,

0.25 mole of magnesium sulphate is formed when 0.25 mole of magnesium reacts.

Now,

Mol. wt. of MgSO

4

=120g

Therefore,

Wt. of 0.25 moles of MgSO

4

=0.25×120=30g

Hence 30g of magnesium sulphate is formd when 6g of magnesium reacts with excess of H

2

SO

4

.

Answer 2

Explanation:

that's help you thank you