Balance the following equations by ion electron method in acid medium
No3 + h2s -> hso4 + nh4
Answers
Answer:
option is
B
8H
2
S+16NO
3
−
+16H
+
⟶16NO
2
+S
8
+16H
2
O
The unbalanced redox equation is as follows:
H
2
S+NO
3
−
⟶NO
2
+S
8
(acidic)
Balance all atoms other than H and O.
8H
2
S+NO
3
−
⟶NO
2
+S
8
(acidic)
The oxidation number of S changes from -2 to 0. The change in the oxidation number per S atom is 2.
Total change in oxidation number for 8 S atoms is 16.
The oxidation number of N changes from 5 to 4. The change in the oxidation number is 1.
So, to balance the increase in the oxidation number with decrease in the oxidation number multiply NO
3
−
and NO
2
with 16.
8H
2
S+16NO
3
−
⟶16NO
2
+S
8
(acidic)
To balance O atoms add 16 water molecules on RHS and to balance H atoms, add 16 H
+
on LHS.
8H
2
S+16NO
3
−
+16H
+
⟶16NO
2
+S
8
+16H
2
O
This is the balanced chemical equation