Question

Balance the following equations
C₃ H8 + O2= CO2 + H₂O​

Answer 1

Answer:

$C₃ H8 + 5O2= 3CO2 + 4H₂O$

Notice We multiplied it by 4 because we want to have 8 hydrogens on both sides. We have multiply the CO² by 3 to match the amount of C as on the LHS.

The last step is to determine the coefficient of the oxygen gas on the LHS. We see that we have

$6 + 4 = 10$

oxygen molecules on the RHS, so we will have

$\frac{10}{2} = 5$

molecules on the LHS. The final balanced chemical equation is:

C₃ H8 + 5O2= 3CO2 + 4H₂O