Balance the following equations:
Cl, +H.0 → HCl + 0,
Answers
Answer:
I think u can understand ......
Explanation:
Writing the oxidation number of all the atoms.
K2+1Cr2+6O7−2+K+1Cl−1+Cr+3Cl3−1+H2O+1−2+Cl20
The Ox. No. of Cr has decreased while has sdecreased while that of chlorine has increased.
K2Cr2+6O7→2CrCl3...(i)+3
HCl−1→Cl0..(ii)
Decrease in Ox. no. of Cr=6 units per molecule K2Cr2O7
Increase in Ox. no. of Cl=1 unit per moleule HCl Eq. (ii) is multiplied by 6.
K2Cr2O7+6HCl→2CrCl3+3Cl2
To balance chlorine and potassium, 14 molecules of HCl of required.
K2Cr2O7+14HCl→2CrCl3+3CrCl3+3Cl2+2KCl
To balance hydrogen and oxygen. 7H2O are added to RHS Hence, the balanced equation is
K2Cr2O7+14HCl→2KCl+2CrCl3+3Cl2+7H2O
Answer:
I think u can understand ......
Explanation:
Writing the oxidation number of all the atoms.
K2+1Cr2+6O7−2+K+1Cl−1+Cr+3Cl3−1+H2O+1−2+Cl20
The Ox. No. of Cr has decreased while has sdecreased while that of chlorine has increased.
K2Cr2+6O7→2CrCl3...(i)+3
HCl−1→Cl0..(ii)
Decrease in Ox. no. of Cr=6 units per molecule K2Cr2O7
Increase in Ox. no. of Cl=1 unit per moleule HCl Eq. (ii) is multiplied by 6.
K2Cr2O7+6HCl→2CrCl3+3Cl2
To balance chlorine and potassium, 14 molecules of HCl of required.
K2Cr2O7+14HCl→2CrCl3+3CrCl3+3Cl2+2KCl
To balance hydrogen and oxygen. 7H2O are added to RHS Hence, the balanced equation is
K2Cr2O7+14HCl→2KCl+2CrCl3+3Cl2+7H2O