Question

Balance the following equations in acidic medium by both oxidation number and ion electron methods and identify the oxidants and the reductants. H2S + Cl2 ----->S + Cl-

Answer 1

Answer:

MnO

4

−

+C

2

H

2

O

4

⇌Mn

2

+CO

2

+H

2

O

Mn

+7

O

−2

4

−

+

C

2

+3

H

2

+1

O

4

−2

⇌

Mn

2

0

+

C

+4

O

2

−2

+

H

2

+

O

−2

Oxidation:

C

2

+3

H

2

1

O

4

−2

⟶

C

+4

O

2

−2

Rediuction:

Mn

+7

O

4

−

−2

⟶

Mn

2

0

Balancing on both sides;

O:C

2

H

2

O

4

⟶2CO

2

+2H

+

R:2MnO

4

−

⟶Mn

2

+8H

2

O

⇒O:C

2

H

2

O

4

⟶2CO

2

+2H

+

+2e

−

R:14e

−

+2MnO

4

−

+16H

+

⟶Mn

2

+8H

2

O

__________________________________________

7C

2

H

2

O

4

⟶14CO

2

+14H

+

+14e

−

2MnO

4

−

+16H

+

+14e

−

⟶Mn

2

+8H

2

O

⇒7C

2

H

2

O

4

+2MnO

4

−

+16H

+

+14e

−

⇌14CO

2

+MN

2

+14H

+

+8H

2

O+14e

−