Balance the following equations:
NaHCO3+H2SO4 Na2SO4+ H20+ CO2
KMn04+ HCI KCI+MnCl2+H20+Cl2
NH3 + 02 N2 +H20
Fe + HCI FeCl2+H2
MnO2+HCI MnCl2+H20+Cl2
Answers
Answered by
1
Answer:
+1
KM
+7
nO
4
−2
+
+3
C
2
O
4
−2
H
2
+1
+
1
H
2
S
6
O
4
−2
⇌
1
K
2
S
6
O
4
−2
+
2
MnS
8
O
4
−2
+
4
CO
2
−2
+
1
H
2
O
−2
Oxidation:
3
C
2
O
4
−2
H
2
1
⟶2
C
6
O
2
−2
+2e
−
Reduction: KMnO
4
⟶Mn
+2
S
6
O
4
−2
⇒ O: C
2
O
4
H
2
⟶2CO
2
+2e
−
+2H
+
R: 2KMnO
4
+3H
2
SO
4
+10e
−
+10H
+
⟶2MnSO
4
+K
2
SO
4
+8H
2
O
⇒ O: 5C
2
O
4
H
2
⟶10CO
2
+10e
−
+10H
+
R: 2KMnO
4
+3H
2
SO
4
+10e
−
+10H
+
⟶2MnSO
4
+K
2
SO
4
+8H
2
O
∴5C
2
O
4
H
2
+2KMnO
4
+3H
2
SO
4
⟶2MnSO
4
+10CO
2
+K
2
SO
4
+8H
2
O .
Explanation:
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