Question

balance the following equtation
pbo+c---->pb+co2

Answer 1

We are asked to balance the following chemical equation:

a. ${\sf{PbO + C \: \longrightarrow Pb \: + CO_2}}$

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Reactants &\bf Products \\\frac{\quad \quad \quad\quad\quad \quad\quad\quad}{}&\frac{\quad \quad \quad\quad\quad \quad\quad\quad}{}\\\sf Pb = 1 & \sf Pb = 1 \\ \\ \sf O = 1 & \sf O = 2 \\ \\ \sf C = 1 & \sf C = 1 \end{array}}\end{gathered}$

»»» Here, O is 1 and 2 as reactants and products respectively. So there is a need to balance it!

${\sf{:\implies PbO + C \: \longrightarrow Pb \: + CO_2}}$

• We can multiply 1 by 2 to make oxygen as 0 in reactants.

${\sf{:\implies 2PbO + C \: \longrightarrow Pb \: + CO_2}}$

»»» Now we are able to see that here O is balanced but now Pb is unbalanced on the products side. As Pb is 2 and 1 as reactants and products respectively. So there is a need to balance it!

${\sf{:\implies 2PbO + C \: \longrightarrow 2Pb \: + CO_2}}$

• Henceforth, balanced!

• ${\small{\boxed{\boxed{\bf{2PbO + C \: \longrightarrow 2Pb \: + CO_2}}}}}$