Balance the following redox equation by electro-ion method: Cl2 + IO3 - -----> Cl- + IO4 - (In Basic Medium)
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Answer:
Cl₂+ IO₃⁻ + 2OH⁻ -------->2Cl⁻ +IO₄⁻ + H₂O in basic medium
Explanation:
Cl₂+2e⁻-------->2Cl⁻ (equation i )
IO₃⁻ + H₂O -------->IO₄⁻+ 2e⁻ (Equation number ii)
Adding equation i and ii
Cl₂+ IO₃⁻ + H₂O -------->2Cl⁻ +IO₄⁻ + 2H⁺ in acidic medium
for basic medium add same amount of OH⁻ as H⁺
because H⁺ + OH⁻ ----> H₂O
Cl₂+ IO₃⁻ + H₂O+2OH⁻ -------->2Cl⁻ +IO₄⁻ + 2H⁺ + 2OH⁻
Cl₂+ IO₃⁻ + H₂O+2OH⁻ -------->2Cl⁻ +IO₄⁻ + 2H₂O
Cl₂+ IO₃⁻ + 2OH⁻ -------->2Cl⁻ +IO₄⁻ + H₂O
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