balance the following redox equations by ion-electron (half reaction method)
please show steps too
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Answer:
Fe
2+
+Cr
2
O
7
2−
+H
+
⟶Fe
3+
+Cr
3+
+H
2
O
(1) Oxidation: Fe
2+
→Fe
3+
Reduction:
Cr
+6
2
O
7
2−
⟶
C
+3
r
3+
(2) Balancing the atoms
Fe
2+
⟶Fe
3+
Cr
2
O
7
2−
+14H
+
⟶2Cr
3+
+7H
2
O
(3) Balance the charge
Fe
2+
⟶Fe
3+
+e
−
⟶(1)
Cr
2
O
7
2−
+14H
+
+6e
−
⟶2Cr
3+
+7H
2
O⟶(2)
(4) Equation (1) ×6+ Equation (2) ×1 Balancing electrons
6Fe
2+
+Cr
2
O
7
2−
+14H
+
+6e
−
⟶6Fe
3+
+2Cr
3+
+6e
−
+7H
2
O
(5) Simplifying;
6Fe
2+
+Cr
2
O
7
2−
+14H
+
⟶6Fe
3+
+2Cr
3+
+7H
2
O
Explanation:
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