balance the following redox reaction by half reaction method Fe+2---> Fe+3+Cr+3 (aq) cauels misdium
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Answer:
Fe2+→Fe3+ + Cr+3
Fe2+→Fe3+ + 1e
Cr+3 + 6e→2Cr
6Fe2+ →6Fe3+ + 6e
Cr3+ +6e →2cr
6Fe2+ + cr3+→6Fe3+ + 2Cr
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