Balance the following redox reaction by ion – electron method :
Cr2O7
2-
(aq) + SO2 (g) Cr3+ (aq) + SO4
2-
(aq) (acidic medium)
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Answer:
Answer(a)-
Half-reaction
oxidation half SO_{2}+2H_{2}O\rightarrow SO_{4}^{2-}+4H^{+}+2e^{-}
reduction half Cr_{2}O_{7}^{2-}+14H^{+}+6e^{-}\rightarrow 2Cr^{3+}+3SO^{2-}+H_{2}O
balancing them by multiplying oxidation half by 3 and adding the reaction
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