Balance the following redox reaction in acidic medium by ion electron method.
Cr202 (aq) + SO2(g) → Cr3+(aq.) + SO? (aq.)
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The oxidation half reaction is SO2(g)+2H2O(l)→SO42−+4H+(aq)+2e−.
The reduction half reaction is Cr2O72−(aq)+14H+(aq)+6e−→2Cr3+(aq)+7H2O(l).
The oxidation half reaction is multiplied by 3 and added to the reduction half reaction to obtain the balanced redox reaction.
Cr2O72−+3SO2(g)+2H+(aq)→2Cr3+(aq)+3SO42−(aq)+H2O(l)
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