Balance the following redox reaction usung any method- Cu+NO3- -> Cu2+ +NO +H2O in acidic medium
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Cu → (Cu2+) + 2e-
(NO3-) + (2H+) + 2e- → (NO2-) + H2O
______________________________
Cu + (NO3-) + (2H+) → (Cu2+) + (NO2-) + H2O*
*You may see H2O in reactant side, but actually it will be in product side, application defect
Cu → (Cu2+) + 2e-
(NO3-) + (2H+) + 2e- → (NO2-) + H2O
______________________________
Cu + (NO3-) + (2H+) → (Cu2+) + (NO2-) + H2O*
*You may see H2O in reactant side, but actually it will be in product side, application defect
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