Balance the given reaction in acidic medium.
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H2O2(aq) + Fe2+(aq) ----------> Fe3+(aq) +H2O(l) {IN ACIDIC MEDIUM}
THE ANSWER IS - H2O2 + 2 H+ + 2Fe2+ ---> 2 H2O + 2Fe3+
via ionic half reactions , I GOT -
Fe2+ ---> Fe3+ + 1e-
as we are oxidizing ferrous ion to ferric ion - hence the loss of the electron; something has to be reduced i.e. h202
H2O2 + 2 H+ + 2 e- ---> 2 H2O
now since we consume 2 electrons in the H2O2 half reaction we need to double the first reaction to off set the electrons and combine
H2O2 + 2 H+ + 2 e- + 2Fe2+ ---> 2 H2O + 2Fe3+ + 2e-
finally you see the 2e- on both sides of the --> so you remove them to show
H2O2 + 2 H+ + 2Fe2+ ---> 2 H2O + 2Fe3+
DO MARK IT AS BRAINLIEST IF DESERVABLE ...
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