Question

Balance the given reaction-KOH + H3PO4
->K3PO4 + H2O
O (a) 3KOH + H3PO4 -> K3PO4 + 3H2O
O (b) 3KOH + 2H3PO4 -> K3PO4 + 3H2O
(c) KOH + 2H3PO4 -> K3PO4 + H2O
O (d) None of the above​

Answer 1

Answer:

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Answer 2

Correct Question :

Balance the given chemical reaction :

KOH + H₃PO₄ $\longrightarrow$ K₃PO₄ + H₂O

(a) 3KOH + H₃PO₄ $\longrightarrow$ K₃PO₄+ 3H₂O

(b) 3KOH + 2H₃PO₄ $\longrightarrow$ K₃PO₄ + 3H₂O

(c) KOH + 2H₃PO4 $\longrightarrow$ K₃PO₄ + H₂O

(d) None of the above

Explanation :

Consider option(A) ,

3KOH + H₃PO₄ $\longrightarrow$ K₃PO₄ + 3H₂O

Number of atoms of potassium before reaction = 3

Number of atoms of Oxygen before reaction = 3 + 4 = 7

Number of atoms of Hydrogen before reaction = 3 + 3 = 6

Number of atoms of Phosporus before reaction = 1

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Number of atoms of potassium after reaction = 3

Number of atoms of phosphorus after reaction = 1

Number of atoms of oxygen after reaction = 4 + 3 = 7

Number of atoms of Hydrogen after reaction = 3(2) = 6

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The number of atoms of all reactants is equal to the number of atoms of the products.

∴ The Balanced chemical reaction for the given one is 3KOH + H₃PO₄ $\longrightarrow$ K₃PO₄ + 2H₂O

Hence , Option(a) is the required answer.