Question

Balance the ionic equation in alkaline medium
Cr(OH)3+IO3-=I- +CrO42-​

Answer 1

Answer:

(IO3)- + (H+) → I2 + H2O First, balance the I and O on both sides: 2(IO3)- + (H+) → I2 + 6H2O Now, balance the H: ... Each iodate needs 5 electrons to reduce to elemental iodine.

Answer 2

Answer:

for cr(oh)3+5oh-=CrO42-+3e+4h2o........................(1)

also for for io3-  

io3-+3h2o=i-+6e +6oh-...................................(2)

from previosly we kow that

cr3+=cr6+ +3e

and I+5=I-1+6e

hence multiply 2with (1)and add with (2)

weget 2cr(oh)3+io3-+4oh-=i-+2cr042- +5h20

Explanation: