Chemistry, asked by meaditi0311, 4 days ago

balance the redox reaction Cr2O7 -²+I- –––> I2 +Cr+³. ​

Answers

Answered by gexig51370
1

Answer:

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Answered by sherylgolden195
0

Answer:

Cr

2

O

7

2−

(aq)+3NO

2

(aq)+8H

+

(aq)⟶2Cr

3+

(aq)+3NO

3

(aq)+4H

2

O(l)

The unbalanced chemical equation is as follows:

Cr

2

O

7

2−

(aq)+HNO

2

(aq)⟶Cr

3+

(aq)+NO

3

(aq)

Balance all atoms other than H and O.

Cr

2

O

7

2−

(aq)+HNO

2

(aq)⟶2Cr

3+

(aq)+NO

3

(aq)

The oxidation number of Cr changes from +6 to +3. The change in the oxidation number is 3.

Total change in the oxidation number is 6.

The oxidation number of N changes from +3 to +5. The change in the oxidation number is 2.

To balance the increase in the oxidation number with decrease in oxidation number, multiply NO

2

and NO

3

with 3.

Cr

2

O

7

2−

(aq)+H

+

+3NO

2

(aq)⟶2Cr

3+

(aq)+3NO

3

(aq)

Balance the O atoms by adding 4 water molecules on RHS.

Cr

2

O

7

2−

(aq)+H

+

+3NO

2

(aq)⟶2Cr

3+

(aq)+3NO

3

(aq)+4H

2

O

Balance H atoms by adding 7H

+

ions on LHS.

Cr

2

O

7

2−

(aq)+8H

+

+3NO

2

(aq)⟶2Cr

3+

(aq)+3NO

3

(aq)+4H

2

O

This is the balanced chemical equation

Explanation:

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