balance the redox reaction mno4- +FeC2O4 gives Fe3+ +mn2+ +2CO2
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Answer:
MnO4- ---------->Mn+2
MnO4- ---------->Mn+2+4H2O
MnO4-+8H --------->Mn+2 +4H2O
2[Mno4-+8H+5e- -------->Mn+2+4H2O]
2MnO4-+16H +10e- ------->2Mn+2+8H2O
...................................................................................
C2o4^_2---------->Co2
C2o4---------->2Co2
[C2o4^_2-------->2Co2+2e-]×5
5C2o4^_2-------->10Co2 +10e-
_____________________________________
2MnO4_+16H+10e-5C2o4^_2-------->2Mn+2+8H2o+10Co2+10 e-
2MnO4_+16H+5C2o4^_2-------->2Mn+2+8H2o+10Co2
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