Question

Balance these equations with the chart :-
(i) MnO2+ KOH+ O2 = K2MnO4+ H2O
(ii) HNO3+ HBr = NO+ Br2+ H2O
(iii) HNO3+ HCL = NO+ Cl2+ H2O

Answer 1

Answer:

i-2 MnO2 + O2 + 4 KOH → 2 K2MnO4 + 2 H2O

ii-2 HNO3 (aq) + 6 HBr (aq) → 2 NO (g) + 3 Br2 (aq) + 4 H2O (l)

iii-0 HNO3 + 0 HCL → 0 NO + 0 Cl2 + 0 H2O

Explanation:

i-this is an oxidation-reduction (redox) reaction:

2 MnIV - 4 e- → 2 MnVI (oxidation)

2 O0 + 4 e- → 2 O-II (reduction)

MnO2 is a reducing agent, O2 is an oxidizing agent.

ii-This is an oxidation-reduction (redox) reaction:

6 Br-I - 6 e- → 6 Br0 (oxidation)

2 NV + 6 e- → 2 NII (reduction)

HBr is a reducing agent, HNO3 is an oxidizing agent.