Balance these euations:(in attached pic)
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1 === .P4 + 5 O2 → P4O10
This is an oxidation-reduction (redox) reaction:
4 P0 - 20 e- → 4 PV
(oxidation)
10 O0 + 20 e- → 10 O-II
(reduction)
P4 is a reducing agent, O2 is an oxidizing agent.
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Answer:
P4 + 5O2 === P4O10
2Mg + O2 === 2MgO
2HgO == 2Hg +O2
2Al2O3 === 4Al + 3O2
Cl2 + 2NaBr == 2Nacl + Br2
2Na + BR2 == 2NaBr 2
CuCl2 + H2S ==== CuS+HCL
2 HgO+Cl2 === HgCl + O2
2KClO3 == 2KCl + 3O2
Bacl2 + Na2SO4 === 2Nacl + BaSO4
Explanation:
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