Balance using partial equation method:- PbS+H2O2=PbSO4+H2O
Answers
Answered by
55
Hey there!
The above is the chemical reaction of Lead sulphide and Hydrogen peroxide forming Lead Sulphate and Water.
Now,
The oxygen in the hydrogen peroxide , must have reacted with Reacted with Lead sulphate .
So, The Oxygen molecule produced two naescent oxygen.
→ { O } + { O }
Now,
PbS + { O } → PbSO4
So, Now, We multiply the Naescent oxygen by 4 .
Now, PbS + 4{ O } → PbSO4 .
Now, [ → { O } + { O } ] by 4 .
It gives, PbS + 4H2O2 → PbSO4 + 4H2O
Now, Pb, S are balanced. also 8 oxygens are on reactants and 8 on products. Hydrogens are also balanced.
So , The balanced equation is PbS + 4H2O2 → PbSO4 + 4H2O
In Partial balancing method ,We look for partial methods involved and balance by Hit & trail method.
The above is the chemical reaction of Lead sulphide and Hydrogen peroxide forming Lead Sulphate and Water.
Now,
The oxygen in the hydrogen peroxide , must have reacted with Reacted with Lead sulphate .
So, The Oxygen molecule produced two naescent oxygen.
→ { O } + { O }
Now,
PbS + { O } → PbSO4
So, Now, We multiply the Naescent oxygen by 4 .
Now, PbS + 4{ O } → PbSO4 .
Now, [ → { O } + { O } ] by 4 .
It gives, PbS + 4H2O2 → PbSO4 + 4H2O
Now, Pb, S are balanced. also 8 oxygens are on reactants and 8 on products. Hydrogens are also balanced.
So , The balanced equation is PbS + 4H2O2 → PbSO4 + 4H2O
In Partial balancing method ,We look for partial methods involved and balance by Hit & trail method.
Answered by
7
Answer:
It gives, PbS + 4H2O - - - > PbSO4 + 4H2O
Explanation:
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