Balance using partial equation method:- PbS+H2O2=PbSO4+H2O
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Answered by
55
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The above is the chemical reaction of Lead sulphide and Hydrogen peroxide forming Lead Sulphate and Water.
Now,
The oxygen in the hydrogen peroxide , must have reacted with Reacted with Lead sulphate .
So, The Oxygen molecule produced two naescent oxygen.
→ { O } + { O }
Now,
PbS + { O } → PbSO4
So, Now, We multiply the Naescent oxygen by 4 .
Now, PbS + 4{ O } → PbSO4 .
Now, [ → { O } + { O } ] by 4 .
It gives, PbS + 4H2O2 → PbSO4 + 4H2O
Now, Pb, S are balanced. also 8 oxygens are on reactants and 8 on products. Hydrogens are also balanced.
So , The balanced equation is PbS + 4H2O2 → PbSO4 + 4H2O
In Partial balancing method ,We look for partial methods involved and balance by Hit & trail method.
The above is the chemical reaction of Lead sulphide and Hydrogen peroxide forming Lead Sulphate and Water.
Now,
The oxygen in the hydrogen peroxide , must have reacted with Reacted with Lead sulphate .
So, The Oxygen molecule produced two naescent oxygen.
→ { O } + { O }
Now,
PbS + { O } → PbSO4
So, Now, We multiply the Naescent oxygen by 4 .
Now, PbS + 4{ O } → PbSO4 .
Now, [ → { O } + { O } ] by 4 .
It gives, PbS + 4H2O2 → PbSO4 + 4H2O
Now, Pb, S are balanced. also 8 oxygens are on reactants and 8 on products. Hydrogens are also balanced.
So , The balanced equation is PbS + 4H2O2 → PbSO4 + 4H2O
In Partial balancing method ,We look for partial methods involved and balance by Hit & trail method.
Answered by
7
Answer:
It gives, PbS + 4H2O - - - > PbSO4 + 4H2O
Explanation:
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