balanced equation of Ehtyne from 1,2 D1 bromo etane
Answers
Answered by
0
Explanation:
CH2Br−CH2Br (alc.KOH) ------> CH2=CHBr (NaNH2)------> CH≡CH (ethyne)
In the reaction first β elimination reaction of the alkyl halide takes place to form the corresponding alkene. This alkene on reaction with sodamide forms corresponding alkyne.(As NaNH
2
is strong base)
Similar questions