Question

Balancing of the Equation 93. The Cr, (a) 144,0, reduces Mno, ion to lo (a) Mn+ (C) Mn3+ (b) Mn2+ (d) Mn 94. 2M read

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Answer 1

The unbalanced chemical reaction is:

Mn3+(aq)→Mn2+(aq)+MnO2(s)+H+(aq)

The oxidation half reaction is, 

Mn3+(aq)→MnO2(s).

To balance oxidation number, one electron is added on R.H.S.

Mn3+(aq)→MnO2(s)+e−

4 protons are added to balance the charge.

Mn3+(aq)→MnO2(s)+4H+(aq)+e−

2 water molecules are added to balance O atoms.

The reduction half reaction is Mn3+(aq)→Mn2+(aq).

An electron is added to balance oxidation number.

Mn3+(aq)+e−→Mn2+(aq)

Two half cell reactions are added to obtain balanced chemical equation.

2Mn3+(aq)+2H2O(l)→Mn2+(aq)+MnO2(s)+4H+(aq)

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