Balancing redox reactions
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Each equation is balanced by adjusting coefficients and adding H2O, H+, and e- in this order:
Balance elements in the equation other than O and H.Balance the oxygen atoms by adding the appropriate number of water (H2O) molecules to the opposite side of the equation.Balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom) by adding H+ ions to the opposite side of the equation. Add up the charges on each side. Make them equal by adding enough electrons (e-) to the more positive side. (Rule of thumb: e- and H+ are almost always on the same side.)The e- on each side must be made equal; if they are not equal, they must be multiplied by appropriate integers (the lowest common multiple) to be made the same.The half-equations are added together, canceling out the electrons to form one balanced equation. Common terms should also be canceled out.(If the equation is being balanced in a basic solution, through the addition of one more step, the appropriate number of OH- must be added to turn the remaining H+ into water molecules.)The equation can now be checked to make sure that it is balanced.
Balance elements in the equation other than O and H.Balance the oxygen atoms by adding the appropriate number of water (H2O) molecules to the opposite side of the equation.Balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom) by adding H+ ions to the opposite side of the equation. Add up the charges on each side. Make them equal by adding enough electrons (e-) to the more positive side. (Rule of thumb: e- and H+ are almost always on the same side.)The e- on each side must be made equal; if they are not equal, they must be multiplied by appropriate integers (the lowest common multiple) to be made the same.The half-equations are added together, canceling out the electrons to form one balanced equation. Common terms should also be canceled out.(If the equation is being balanced in a basic solution, through the addition of one more step, the appropriate number of OH- must be added to turn the remaining H+ into water molecules.)The equation can now be checked to make sure that it is balanced.
rayana:
I got the concept... but I was not able to solve this particular redox reaction, especially reduction half.
Can anyone help with it???
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