balancing the equation question no one koh+h2oso4 is equal to k2so4 +h2o
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Step 1: Number of atoms of each element throughout the given equation is counted. H: 5 S: 2 O : 10 K : 3
Step 2: The element which occurs least number of times is first balanced. Only two S atoms are present in given equation; one S on left hand side and another S on right hand side. So, S is already balanced. The next element which occurs least number of times is K. In the given equation, there are 2 K atoms on right hand side. Hence, there must be 2 K atoms on left hand side and thereby 2 KOH on left hand side. H2SO4 + 2 KOH ----- 1 K2SO4 + H2O Thus, K is balanced on both sides of equation. The next element which occurs least number of times is H. In above equation there are four hydrogen atoms on left hand side and hence there must be four hydrogen atoms on right hand side and therefore, it must be 2 H2O on right hand side. H2SO4 + 2 KOH ----- K2SO4 + 2 H2O The next and last element to be balanced is O. In the above equation, there are 6 O atoms on each side of the equation. Hence, O is balanced in the above equation. Thus, all elements are balanced. Hence, the balanced chemical equation is, H2SO4 + 2 KOH ----- K2SO4 + 2 H2O
Physical states of substances may also be indicated in the balanced chemical equation as shown here: H2SO4 (aq) + 2 KOH (aq) ----- K2SO4 (aq) + 2 H2O (l) ((aq) means aqueous solution of the compound or solution of the compound in water. (l) means liquid state). Hit and trial method H2SO4 + ___KOH ----- ___K2SO4 + H2O There are 2 K atoms on right hand side and therefore there must be 2 K atoms on left hand side of the equation. Hence, it must be 2 KOH on left hand side of the equation. H2SO4 + 2 KOH ----- 1 K2SO4 + H2O The number of S atoms is same on both sides of the equation. There are 6 O atoms on left hand side and hence there must be 6 O atoms on right hand side. Hence, it must be 2 H2O on right hand side. H2SO4 + 2 KOH ----- K2SO4 + 2 H2O Number of hydrogen atoms on each side of above equation is 6 and hence, number of hydrogen atoms is balanced. Thus, all elements are balanced in the equation. Hence, balanced chemical equation is, H2SO4 + 2 KOH ----- K2SO4 + 2 H2O
Step 2: The element which occurs least number of times is first balanced. Only two S atoms are present in given equation; one S on left hand side and another S on right hand side. So, S is already balanced. The next element which occurs least number of times is K. In the given equation, there are 2 K atoms on right hand side. Hence, there must be 2 K atoms on left hand side and thereby 2 KOH on left hand side. H2SO4 + 2 KOH ----- 1 K2SO4 + H2O Thus, K is balanced on both sides of equation. The next element which occurs least number of times is H. In above equation there are four hydrogen atoms on left hand side and hence there must be four hydrogen atoms on right hand side and therefore, it must be 2 H2O on right hand side. H2SO4 + 2 KOH ----- K2SO4 + 2 H2O The next and last element to be balanced is O. In the above equation, there are 6 O atoms on each side of the equation. Hence, O is balanced in the above equation. Thus, all elements are balanced. Hence, the balanced chemical equation is, H2SO4 + 2 KOH ----- K2SO4 + 2 H2O
Physical states of substances may also be indicated in the balanced chemical equation as shown here: H2SO4 (aq) + 2 KOH (aq) ----- K2SO4 (aq) + 2 H2O (l) ((aq) means aqueous solution of the compound or solution of the compound in water. (l) means liquid state). Hit and trial method H2SO4 + ___KOH ----- ___K2SO4 + H2O There are 2 K atoms on right hand side and therefore there must be 2 K atoms on left hand side of the equation. Hence, it must be 2 KOH on left hand side of the equation. H2SO4 + 2 KOH ----- 1 K2SO4 + H2O The number of S atoms is same on both sides of the equation. There are 6 O atoms on left hand side and hence there must be 6 O atoms on right hand side. Hence, it must be 2 H2O on right hand side. H2SO4 + 2 KOH ----- K2SO4 + 2 H2O Number of hydrogen atoms on each side of above equation is 6 and hence, number of hydrogen atoms is balanced. Thus, all elements are balanced in the equation. Hence, balanced chemical equation is, H2SO4 + 2 KOH ----- K2SO4 + 2 H2O
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