Question

Bali has three sons, he had some chocolate. He have his eldest son 3 more than half of what he has. He gave his second eldest son 4 more than 1/3 of what he has left and he gave his youngest 4 more 1/4 of what is left . He is left with 11 chocolate s , how many chocolate s did he have initially?

Answer 1

Bali has 3 sons
Let the no of chocolate he has be x chocolates

Acc to the question

※To the eldest child:
(X/2)+4 .................................................... (1)

Chocolate left=x-[(x/2)+4] = (x-6)/2 ................................(2)

※to the secound eldest:
1/3[(x-6)/2]+4 = (x+18)/6 ............................(3)

Chocolate left is (2)- (3)
=(x-18)/3 .............................................(4)

※ to the youngest child:
1/4[(x-18)/3]+4 =(x+30)/2 ......................................(5)

Chocolate left (4)-(5)
=(x-34)/4 ..........................................(6)

Given in question that the balance chocolate left is 11
Therefore equating ...(6) = 11
(X-34)/4=11
X-34=44
X=78 the initial no of chocolate he had.!!