Question

ball A having a mass 0.05 kg moving to the right at velocity of 0.50 m/sec makes an headon collision with a ball B of having amass of 0.20 kg that is initally at rest after the colliion ball a moves to the left at 0.30 m/sec find the final velocity of ball

Answer 1

Answer:

Explanation:Mass of each ball =0.05kg

Initial velocity of each ball =6m/s

Magnitude of the initial momentum of each ball,  P

i

​

=mv

i

​

=0.05×6=0.3 kg m/s

After collision, the balls change their directions of motion without changing the magnitudes of their velocity.

Final momentum of first ball, P

1f

​

=−0.3 kg m/s

Final momentum of second ball, P

2f

​

=0.3 kg m/s

Impulse imparted to first ball = P

1f

​

−P

1i

​

=−0.3−0.3 kg m/s=−0.6 kg m/s

Impulse imparted to second ball =  P

2f

​

−P

2i

​

=0.3−(−0.3)=0.6 kg m/s

The negative sign indicates that the impulses imparted to the balls are opposite in direction.