Question

Ball A is dropped from a building and at the same instant that a another ball B is thrown vertically upward from the ground when both balls collide they are moving in opposite directions and speed of A is twice the speed of B at what function of height of the building the collision occur​

Answer 1

Answer:

Let the building be of height H and let the balls collide at h and time t

Distance travelled by A

H−h=12gt2

So

t2=2g(H−h)

And distance covered by B is

h=ut−12gt2

Subsisting the value of t

h=u2(H−h)g−−−−−−−−√−(H−h)

Squaring after doing appropriate simplification

H2=2u2(H−h)g

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