Question

Ball A is dropped from the top of a building. One second later, ball B is dropped from the same building. Neglect air resistance. As time progresses, the difference in their speeds *​

Answer 1

Answer:

This is the answer

Explanation:

let the velocity of ball A be = VA

let the velocity of ball B be = VB

so

VA = gravitational acceleration * time

VA = gt

VB = g * (t-1)

therfore

VA - VB = gt  - (g*(t-1)) = gt - gt + g = g = 10m/s or 9.8m/s