Question

ball is thrown upwards from a rooftop which is above from the ground. It will reach a maximum vertical height and

then fall back to the ground. The height of the ball "h" from the ground at time "t" seconds is given by, h = -16t² + 64t

+ 80.How long will the ball take to hit the ground?​

Answer 1

Answer:

hey apply formula h= 1/2gt2 you will get your answer

Answer 2

Answer:

Step-by-step explanation:

To find the time it takes for the ball to hit the ground, we need to find the time when the height of the ball is 0.

We can set the equation for the height of the ball equal to 0:

-16t^2 + 64t + 80 = 0

We can solve this quadratic equation using the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / 2a

where a = -16, b = 64, and c = 80. Plugging in these values, we get:

t = (-64 ± √(64^2 - 4(-16)(80))) / 2(-16)

= (64 ± √(4096 + 5120)) / -32

= (64 ± √9216) / -32

= (64 ± 96) / -32

So, the two values for t are:

t = (64 - 96) / -32 = -32 / -32 = 1

t = (64 + 96) / -32 = 160 / -32 = -5

Since the time cannot be negative, the ball takes t = 1 second to hit the ground.