Question

ball is thrown vertically upwards with a velocity of 15 m s−1 from the top of the building of height 50 m. (a) how long will it take to reach the base of the tower? (b) with what velocity it hits the ground?​

Answer 1

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t

′

)

2

t

′

=3s

Total time= 3+2= 5s

Explanation:

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Answer 2

Answer:

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