ball of mass 3 kg and 9 kg are dropped together from 60 feet after fall of 45 feet their KE will be in ratio of
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1:3
Explanation:
Given that Mass m1=3, m2=9
As both balls are falling through the same height therefore they possess the same velocity
KE=0.5mv^2
kinetic engery is directly proportional to mass
or,
KE α m......(v is constant)
KE1/KE2= m1/m2 = 3/9 = 1/3
hence req. ration is 1:3
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