Question

ball thrown up in the air reaches a maximum height of 45 meter and travels a horizontal distance of 75 meter trans the path of the boll assuming it to be Parabolic

Answer 1

Answer:

26 meter us to be a night watchman so that he could

Answer 2

Therefore the path of the ball makes an angle of 67.38° with the horizontal.

Given:

The maximum height reached by the ball = H = 45 m

The horizontal distance traveled by the ball = R = 75 m

To Find:

The path of the ball or the angle of the ball(θ).

Solution:

The given question can be solved as shown below.

Given that,

The maximum height reached by the ball = H = 45 m

The horizontal distance traveled by the ball = R = 75 m

The height attained by the ball is given by,

⇒ H = ( u² sin²θ )/2g         (i.)

The horizontal distance traveled by the ball is given by,

⇒ R = ( u² sin2θ )/g           (ii.)

Dividing (i.) and (ii.) equations,

⇒ H/R = [ ( u² sin²θ )/2g ]/[ ( u² sin2θ )/g ]

⇒ 45/75 = ( sin²θ/2 )/(2sinθcosθ)

⇒ 3/5 = sinθ/4cosθ

⇒ 12/5 = tan θ

⇒ θ = 67.38°

Therefore the path of the ball makes an angle of 67.38° with the horizontal.

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