Question

ball thrown with velocity of 20m/s will come back to ground in how much time?

Answer 1

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t²)

t = 3s

Total time= 3+2= 5s

Answer 2

Answer:

v=—20m/s back thrown in ball.

u=0

a=0

v=u+at

at=v—u

at=—20—0

at=20

t=a×20

t=0×20

t=0 answer