Question

Balloon rises with a constant velocity v aloud move relative to earth if the rope is suddenly cut off when be balloon is at height h. Also find the time taken by load to reach the earth. With what velocity it lands the earth?

Answer 1

Answer:

gravity extract to the earth

Answer 2

Answer:

0

Explanation:

Analysis of situation: t = 0 is the time when the balloon started rising up. At t = 0, when the packet is dropped, the balloon is moving up with velocity v = 0 + at  

0

​

 = at  

0

​

. Hence, initial velocity of the packet will be v  

0

​

=at  

0

​

 (upward). As the balloon has started rising upwards with constant acceleration a, so after t  

0

​

 seconds, its height from the ground is y  

0

​

=  

2

1

​

at  

0

2

​

.

For packet: s = ut -  

2

1

​

gt  

2

 

⇒  −  

2

1

​

at  

0

2

​

 = at  

0

​

t−  

2

1

​

gt  

2

 ⇒  gt  

2

−2at  

0

​

t−at  

0

2

​

=0

Solving the quadratic equation, we get t =  

g

at  

0

​

 

​

[1+  

1+  

a

g

​

 

​

]