Math, asked by kaviyasundar06, 6 hours ago

balls are tossed at random into 50 boxes. Find the expected no of boxes required to get the first ball in the fourth box​

Answers

Answered by hetu88
0

Step-by-step explanation:

in 50 boxed

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due to some copy right oss issue the answer is like this but the answer is 5444

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Answered by SteffiPaul
0

Therefore the probability of getting the ball in the 4th box in the first attempt is 0.0625.

Given:

There are 50 boxes in which the balls are to be tossed.

To Find:

The expected probability of getting the first ball in the fourth box.

Solution:

The given question can be solved by the below-shown approach.

The total number of boxes is 50 which are numbered from 1 to 50.

The ball is thrown into each box starting from 1 to 50 but the ball does not fall into the first 3 boxes and it falls in the 4th box.

So after 3 attempts, we have a total of 47 boxes.

So in the first 3 boxes, the ball may fall or may not fall. Hence both the cases have an equal probability that is 0.5.

Probability of falling in the box = 0.5

Probability of not falling in the box = 0.5

The probability of the ball not falling in the first 3 boxes = 0.5³

The probability of the ball falling in the fourth box after not falling in the first 3 boxes = 0.5³ × 0.5 = 0.5⁴ = 0.0625

Therefore the probability of getting the ball in the 4th box in the first attempt is 0.0625.

#SPJ2

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