Balls fall on the ground from height 98 m .what is time
Answers
Answered by
1
Answer:
4
seconds
Earth's acceleration due to gravity is 9.8m/s^2
this means that anything's velocity changes by 9.8m/s every second.
1s=t v=9.8 d
2s= t v=19.6
t=3s v=29.4
t=4s d=39.2
addition = 98
because 1st second it travel 9.8m
2nd second=19.6
and so on
Answered by
0
The distance is 98 m. S
Acceleration is 9.8 m/s^2 .a
Find time .t
By third equation of motion
S=ut +1/2 at^2
Here u is initial velocity .
Initial velocity is 0 so the equ is
S=1/2 at^2.
Substitute the value,
98=1/2 *9.8*t^2
98= 9.8/2 *t^2
98= 4.9*t^2
98/4.9=t^2
20=t^2
4.5 sec =t
Ans 4.5 sec
Acceleration is 9.8 m/s^2 .a
Find time .t
By third equation of motion
S=ut +1/2 at^2
Here u is initial velocity .
Initial velocity is 0 so the equ is
S=1/2 at^2.
Substitute the value,
98=1/2 *9.8*t^2
98= 9.8/2 *t^2
98= 4.9*t^2
98/4.9=t^2
20=t^2
4.5 sec =t
Ans 4.5 sec
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