Math, asked by ashajaya5165, 5 hours ago

Balus age was 3 times bijus age after 2yers it would doublee the present age of balu is x and bijus y what is the age of balu and biju 4years back

Answers

Answered by s04328fannielois
0

Answer:

Given:-

Four years ago,balu's age was 3 times biju's age.

After 2 years it would be just double .

To find:-

Their present age.

Solution:-

Let present age of balu = x

And present age of biju=y.

4 yrs ago :-

Age of balu = (x-4)

Age of biju = (y-4)

After 2 yrs:-

Age of balu = x + 2

Age of biju = y +2

Acc to question :-

Given that,

Balu's age = 3 times of biju's age 4 years ago .

=> (x-4)=3(y-4)

=> x-4 = 3y - 12

=> x-3y = -8 (1)

After 2 yrs it would be double .

=> (x+2)=2(y+2)

=> x+2 = 2y +4

=> x-2y = 2 (2)

Solving eqn (1)&(2) :-

x - 3y = -8

x - 2y =  2

-y = -10

  y = 10

Now,

x - 3y  = -8

x - 3(10) = -8

x =  30 - 8

x = 22.

And we're done !

Therefore ,

Age of balu = 22 years.

Age of biju = 10 years.

____________________

Step-by-step explanation:

Hope this helps

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