Question

Balwinder father had a rhombus shaped plot with diagonal 20 and 40 meter long. he sold a plot and bought a square shaped plot of same area. find the perimeter of the plot​

Answer 1

Answer:

Step-by-step explanation:

Given,

Diagonals of rhombus = 20 and 40

According to the question,

Ar. Of rhombus = Ar. Of square

1/2(20×40) = s×s

400= s×s

Therefore S=20 (side of square)

Now,

Perimeter of square =4s

=4×20

=80 sq.meter

Answer 2

Answer:

80 m.

Step-by-step explanation:

Given:

First diagonal of the Rhombus = 20 m

Second diagonal of the Rhombus = 40 m

We know that,

area of a Rhombus = 1/2 * d(1)*d(2)

= 1/2*20*40

= 800/2

= 400 m²

And also given that,

Area of the Rhombus = Area of Square

We know that, area of a square = (side)²

Hence, 400 m² = (s)²

(20)² = (s)²

s = √(20)²

S = 20 m

We know that, perimeter of a square = 4*side

= 4*20

Perimeter of a square = 80 m