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3). In AABC the measure of angle A is more by 40 than the sum of
the measures of Bad ZC. Also the ratio of memur ZB
and 2C is 4:3. Then find the measures of angle of the triangle
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Answer:
In △OAB,
OA = OB [radii of same circle]
∠OBA = ∠OAB = 40° [∠s opp. to equal sides in a △ are equal]
Now, ∠OAB + ∠AOB + ∠OBA = 180° [angle sum properly of a △]
⇒ 40° + ∠AOB + 40° = 180°
⇒ ∠AOB = 100°
Therefore, ∠ACB = 50° [∵ angle
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