Banayi has 3 times as many 2 rupee coins as the number of 5 rupee coins he has. If he has in all a sum of rs77, how many coins of each denomination he has.
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let the 5 Rs coin be x
Then the 2rs coin be 3x
Total amuont
from Rs 5=5*x=5x
from Rs2=2*3x=6x
Total=6x+5x=11x
sum os all rs=77
A/q
11x=77
x=77/11
x=7
The 5 Rs coin =x=7
Then the 2rs coin =3x=3*7=21
let the number of notes be x
let the no. of notes of rs 50 be 3x
let the no. of notes of rs 20 be 5x
but she has total no of notes =25
then no. of notes of rs 10=25-(5x+3x)
=25-8x
total amount from
Rs 50=50*3x=150x
Rs 20=20*5x=100x
Rs 10=10*(25-8x)=250-80x
hence total amount=170x+250
total currency is 590 rs
A/q
170x+250=590
170x=590-250
170x=340
x=340/170
x=2
the no. of notes of rs 50 is 3x=3*2=6
the no. of notes of rs 20 is 5x=5*2=10
no. of notes of rs 10=25-8x=25-8*2
=25-16
=9
Then the 2rs coin be 3x
Total amuont
from Rs 5=5*x=5x
from Rs2=2*3x=6x
Total=6x+5x=11x
sum os all rs=77
A/q
11x=77
x=77/11
x=7
The 5 Rs coin =x=7
Then the 2rs coin =3x=3*7=21
let the number of notes be x
let the no. of notes of rs 50 be 3x
let the no. of notes of rs 20 be 5x
but she has total no of notes =25
then no. of notes of rs 10=25-(5x+3x)
=25-8x
total amount from
Rs 50=50*3x=150x
Rs 20=20*5x=100x
Rs 10=10*(25-8x)=250-80x
hence total amount=170x+250
total currency is 590 rs
A/q
170x+250=590
170x=590-250
170x=340
x=340/170
x=2
the no. of notes of rs 50 is 3x=3*2=6
the no. of notes of rs 20 is 5x=5*2=10
no. of notes of rs 10=25-8x=25-8*2
=25-16
=9
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