Math, asked by ruhi58, 1 year ago

Banayi has 3 times as many 2 rupee coins as the number of 5 rupee coins he has. If he has in all a sum of rs77, how many coins of each denomination he has.

Answers

Answered by rajeswar
2
 let the 5 Rs coin be x 
Then the 2rs coin be 3x 
Total amuont 
from Rs 5=5*x=5x 
from Rs2=2*3x=6x 
Total=6x+5x=11x 
sum os all rs=77 
A/q 
11x=77 
x=77/11 
x=7 
The 5 Rs coin =x=7 
Then the 2rs coin =3x=3*7=21 

let the number of notes be x 
let the no. of notes of rs 50 be 3x 
let the no. of notes of rs 20 be 5x 
but she has total no of notes =25 
then no. of notes of rs 10=25-(5x+3x) 
=25-8x 
total amount from 
Rs 50=50*3x=150x 
Rs 20=20*5x=100x 
Rs 10=10*(25-8x)=250-80x 
hence total amount=170x+250 
total currency is 590 rs 
A/q 
170x+250=590 
170x=590-250 
170x=340 
x=340/170 
x=2 
the no. of notes of rs 50 is 3x=3*2=6 
the no. of notes of rs 20 is 5x=5*2=10 
no. of notes of rs 10=25-8x=25-8*2 
=25-16 
=9
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