Question

Bansi has 3 time as many two rupees coins as he has five rupees coins. If he has in all sum of ₹77, how many coins of each denomination does he have?
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Answer 1

Answer:

☆ Given:

▪︎Bansi has 3 time as many two rupees coins as he has five rupees coins

▪︎Sum of all coins = ₹77

☆ To find:

No . of 2 rupees coins

And No . of 5 rupees coins

☆ Taken:

Let 2 rupees coin be 2y

And let 5 rupee coin be 5x

So , now the equation will form like this :

2(3x)+5(x)=77

☆ Solution:

>> 2(3x)+5(x)=77

>> 6x+5x=77

>> 11x=77

>> x=77/11

>> x=7

So , the total five rupees coins are 7 .

Now , find the number of 2 rupees coin .

= {77-(5×7)}/2

= {77-35}/2

= 42/2

= 21

☆ Answer:

No . of 5 rupees coin = 7

No . of 2 rupees coin = 21

☆ Extra information:

To find area of the rectangle:

$Ar=L×B$

Where,

Ar = Area of the rectangle

L = Length

B = Breadth

To find area of the triangle:

$At=\frac{H×Ba}{2}$

Where,

At = Area of the triangle

H = Height

Ba = Base

To find area of the square:

$As=S×S$

Where,

As = Area of the square

S = One side of the square