Bansi has 3 times as many two rupee coins as he has five-rupee coins. If he has
in all a sum of Rs. 77, how many coins each denomination does he have?
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5
Answer:
Let Bansi has x coin.
So, coins of ₹2 = 2 * x = 2x
And coins of ₹5 = 5 * x = 5x
From given condition,
=> 3 * (2x) = 6x
Sum of coins = 6x + 5x = 11x
=> 11x = 77
=> x = 77 ÷ 11
=> x = 7
3x = 3 * 7 = 21
Coins of ₹2 = x = 7
Coins of ₹5 = 3x = 3 * 7 = 21
Verification:
=> 42 + 35
=> 77
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