Question

Bansi has 3 times as many two-rupee coins as he has five-rupee coins. Ifhe has in all a sum of ` 77, how many coins of each denomination does he have?​

Answer 1

$\huge\underline{\underline\mathtt{Answer:-}}$:

Solution:

Let the number of five-rupee coins that Bansi has be x. Then the number oftwo-rupee coins he has is 3 times x or 3x.

The amount Bansi has:

(i) from 5 rupee coins, ` 5 × x = ` 5x

(ii) from 2 rupee coins, ` 2 × 3x = ` 6x

Hence the total money he has = ` 11x

But this is given to be ` 77; therefore,

11x = 77

x =77/11

x= 7

Thus, number of five-rupee coins = x = 7

and number of two-rupee coins =

3x = 21 ..................(solution)

Answer 2

Answer:

Let Bansi has x coin.

So, coins of ₹2 = 2 * x = 2x

And coins of ₹5 = 5 * x = 5x

From given condition,

=> 3 * (2x) = 6x

Sum of coins = 6x + 5x = 11x

=> 11x = 77

=> x = 77 ÷ 11

=> x = 7

3x = 3 * 7 = 21

Coins of ₹2 = 6 * 7 = 42

Coins of ₹5 = 5 * 7 = 35

Verification:

=> 42 + 35

=> 77