Question

Bansi has 3 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of Rs 77, how many coins of each denomination does he have?

Answer 1

Answer:

Here is the answer for your question

Step-by-step explanation:

Let Bansi has x five-rupee coins. Then he will have 3x two-rupees coins.

We are given,

5x + 2 × 3x = 77

5x + 6x = 77

11x = 77⇒ x = 7 So Bansi has 7 five-rupees coins and 21 two rupees coins.

Answer 2

Answer:

Let Bansi has x coin.

So, coins of ₹2 = 2 * x = 2x

And coins of ₹5 = 5 * x = 5x

From given condition,

=> 3 * (2x) = 6x

Sum of coins = 6x + 5x = 11x

=> 11x = 77

=> x = 77 ÷ 11

=> x = 7

3x = 3 * 7 = 21

Coins of ₹2 = x = 7

Coins of ₹5 = 3x = 3 * 7 = 21

Verification:

=> 42 + 35

=> 77