Question

Bansi has 3 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of Rs 77, How many coins of each denominations does he have? * 3 points 7,21 3,9 6,18 5,1​

Answer 1

Answer:

five rupee coins be 5x. And two rupee coins be 3(2X ) Given , 5X+6X = 77 . So 11x=77 X=77/11 X=7 Therefore Number of 5 rupee coins =7 and 2 rupee coins =7*3 =21

Answer 2

he has 28 coins of 2 and 5

Step-by-step explanation:

$3(2 + 5) = 77$

$3 \times 7 = 77$

$21 = 77$

$77 - 21$

$= 56$

$56 \div 2$

$= 28$