Barbara wants to earn $500 a year by investing $5000 in two
accounts, a savings plan that pays 8% annual interest and a highrisk
option that pays 13.5% interest. How much should she invest
at 8% and how much at 13.5%? Write a system of equations that
would allow you to solve Barbara’s dilemma
Answers
Answered by
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Solutions
Let x = amount invested at 8%.
Let y = amount invested at 13.5%.
It is given that the total invested in both accounts is $5000. The equation that represents this info is: x + y = 5000. It is also given that the total amount earned from both accounts is $500. The amount earned in the 8% account will be the amount invested times the rate: 0.08x And the amount earned in the 13.5% account will be: 0.135y
Together the two accounts will total $500 earned. The equation will be: 0.08x + 0.135y = 500. Solving this system of 2 equations would give both account values.
Let x = amount invested at 8%.
Let y = amount invested at 13.5%.
It is given that the total invested in both accounts is $5000. The equation that represents this info is: x + y = 5000. It is also given that the total amount earned from both accounts is $500. The amount earned in the 8% account will be the amount invested times the rate: 0.08x And the amount earned in the 13.5% account will be: 0.135y
Together the two accounts will total $500 earned. The equation will be: 0.08x + 0.135y = 500. Solving this system of 2 equations would give both account values.
Answered by
1
Given:
1. Barbara invested $5000 and she wants to earn $500
Need to find out:
The system of equation
Solution:
Let us assume the 8% as X
Let us assume the 13.5% as Y
⇒ X + Y = $5000 ( according to question )
The amount she wants’ to earn in the both situation is 500
By this we can say -
8% would be 0.08x
13.5% would be 0.135y
0.08x + 0.135y = 500 (here we are using 500 because the amount she wants’ is 500)
∴ The system of equation will be "0.08x + 0.135y = 500"
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